Integrand size = 21, antiderivative size = 95 \[ \int \frac {(d+e x)^2 \left (a+b \log \left (c x^n\right )\right )}{x^6} \, dx=-\frac {b d^2 n}{25 x^5}-\frac {b d e n}{8 x^4}-\frac {b e^2 n}{9 x^3}-\frac {d^2 \left (a+b \log \left (c x^n\right )\right )}{5 x^5}-\frac {d e \left (a+b \log \left (c x^n\right )\right )}{2 x^4}-\frac {e^2 \left (a+b \log \left (c x^n\right )\right )}{3 x^3} \]
[Out]
Time = 0.07 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {45, 2372, 12, 14} \[ \int \frac {(d+e x)^2 \left (a+b \log \left (c x^n\right )\right )}{x^6} \, dx=-\frac {d^2 \left (a+b \log \left (c x^n\right )\right )}{5 x^5}-\frac {d e \left (a+b \log \left (c x^n\right )\right )}{2 x^4}-\frac {e^2 \left (a+b \log \left (c x^n\right )\right )}{3 x^3}-\frac {b d^2 n}{25 x^5}-\frac {b d e n}{8 x^4}-\frac {b e^2 n}{9 x^3} \]
[In]
[Out]
Rule 12
Rule 14
Rule 45
Rule 2372
Rubi steps \begin{align*} \text {integral}& = -\frac {d^2 \left (a+b \log \left (c x^n\right )\right )}{5 x^5}-\frac {d e \left (a+b \log \left (c x^n\right )\right )}{2 x^4}-\frac {e^2 \left (a+b \log \left (c x^n\right )\right )}{3 x^3}-(b n) \int \frac {-6 d^2-15 d e x-10 e^2 x^2}{30 x^6} \, dx \\ & = -\frac {d^2 \left (a+b \log \left (c x^n\right )\right )}{5 x^5}-\frac {d e \left (a+b \log \left (c x^n\right )\right )}{2 x^4}-\frac {e^2 \left (a+b \log \left (c x^n\right )\right )}{3 x^3}-\frac {1}{30} (b n) \int \frac {-6 d^2-15 d e x-10 e^2 x^2}{x^6} \, dx \\ & = -\frac {d^2 \left (a+b \log \left (c x^n\right )\right )}{5 x^5}-\frac {d e \left (a+b \log \left (c x^n\right )\right )}{2 x^4}-\frac {e^2 \left (a+b \log \left (c x^n\right )\right )}{3 x^3}-\frac {1}{30} (b n) \int \left (-\frac {6 d^2}{x^6}-\frac {15 d e}{x^5}-\frac {10 e^2}{x^4}\right ) \, dx \\ & = -\frac {b d^2 n}{25 x^5}-\frac {b d e n}{8 x^4}-\frac {b e^2 n}{9 x^3}-\frac {d^2 \left (a+b \log \left (c x^n\right )\right )}{5 x^5}-\frac {d e \left (a+b \log \left (c x^n\right )\right )}{2 x^4}-\frac {e^2 \left (a+b \log \left (c x^n\right )\right )}{3 x^3} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.84 \[ \int \frac {(d+e x)^2 \left (a+b \log \left (c x^n\right )\right )}{x^6} \, dx=-\frac {60 a \left (6 d^2+15 d e x+10 e^2 x^2\right )+b n \left (72 d^2+225 d e x+200 e^2 x^2\right )+60 b \left (6 d^2+15 d e x+10 e^2 x^2\right ) \log \left (c x^n\right )}{1800 x^5} \]
[In]
[Out]
Time = 0.57 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.96
method | result | size |
parallelrisch | \(-\frac {600 b \ln \left (c \,x^{n}\right ) e^{2} x^{2}+200 b \,e^{2} n \,x^{2}+600 a \,e^{2} x^{2}+900 b \ln \left (c \,x^{n}\right ) d e x +225 b d e n x +900 a d e x +360 b \ln \left (c \,x^{n}\right ) d^{2}+72 b \,d^{2} n +360 a \,d^{2}}{1800 x^{5}}\) | \(91\) |
risch | \(-\frac {b \left (10 e^{2} x^{2}+15 d e x +6 d^{2}\right ) \ln \left (x^{n}\right )}{30 x^{5}}-\frac {-180 i \pi b \,d^{2} \operatorname {csgn}\left (i c \,x^{n}\right )^{3}-450 i \pi b d e x \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )+180 i \pi b \,d^{2} \operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}-180 i \pi b \,d^{2} \operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )+600 \ln \left (c \right ) b \,e^{2} x^{2}+200 b \,e^{2} n \,x^{2}+600 a \,e^{2} x^{2}+300 i \pi b \,e^{2} x^{2} \operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}+450 i \pi b d e x \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}-300 i \pi b \,e^{2} x^{2} \operatorname {csgn}\left (i c \,x^{n}\right )^{3}+180 i \pi b \,d^{2} \operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}+900 \ln \left (c \right ) b d e x +225 b d e n x +900 a d e x +450 i \pi b d e x \,\operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}+300 i \pi b \,e^{2} x^{2} \operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}-300 i \pi b \,e^{2} x^{2} \operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )-450 i \pi b d e x \operatorname {csgn}\left (i c \,x^{n}\right )^{3}+360 d^{2} b \ln \left (c \right )+72 b \,d^{2} n +360 a \,d^{2}}{1800 x^{5}}\) | \(403\) |
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.12 \[ \int \frac {(d+e x)^2 \left (a+b \log \left (c x^n\right )\right )}{x^6} \, dx=-\frac {72 \, b d^{2} n + 360 \, a d^{2} + 200 \, {\left (b e^{2} n + 3 \, a e^{2}\right )} x^{2} + 225 \, {\left (b d e n + 4 \, a d e\right )} x + 60 \, {\left (10 \, b e^{2} x^{2} + 15 \, b d e x + 6 \, b d^{2}\right )} \log \left (c\right ) + 60 \, {\left (10 \, b e^{2} n x^{2} + 15 \, b d e n x + 6 \, b d^{2} n\right )} \log \left (x\right )}{1800 \, x^{5}} \]
[In]
[Out]
Time = 0.54 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.23 \[ \int \frac {(d+e x)^2 \left (a+b \log \left (c x^n\right )\right )}{x^6} \, dx=- \frac {a d^{2}}{5 x^{5}} - \frac {a d e}{2 x^{4}} - \frac {a e^{2}}{3 x^{3}} - \frac {b d^{2} n}{25 x^{5}} - \frac {b d^{2} \log {\left (c x^{n} \right )}}{5 x^{5}} - \frac {b d e n}{8 x^{4}} - \frac {b d e \log {\left (c x^{n} \right )}}{2 x^{4}} - \frac {b e^{2} n}{9 x^{3}} - \frac {b e^{2} \log {\left (c x^{n} \right )}}{3 x^{3}} \]
[In]
[Out]
none
Time = 0.20 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.05 \[ \int \frac {(d+e x)^2 \left (a+b \log \left (c x^n\right )\right )}{x^6} \, dx=-\frac {b e^{2} n}{9 \, x^{3}} - \frac {b e^{2} \log \left (c x^{n}\right )}{3 \, x^{3}} - \frac {b d e n}{8 \, x^{4}} - \frac {a e^{2}}{3 \, x^{3}} - \frac {b d e \log \left (c x^{n}\right )}{2 \, x^{4}} - \frac {b d^{2} n}{25 \, x^{5}} - \frac {a d e}{2 \, x^{4}} - \frac {b d^{2} \log \left (c x^{n}\right )}{5 \, x^{5}} - \frac {a d^{2}}{5 \, x^{5}} \]
[In]
[Out]
none
Time = 0.31 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.17 \[ \int \frac {(d+e x)^2 \left (a+b \log \left (c x^n\right )\right )}{x^6} \, dx=-\frac {{\left (10 \, b e^{2} n x^{2} + 15 \, b d e n x + 6 \, b d^{2} n\right )} \log \left (x\right )}{30 \, x^{5}} - \frac {200 \, b e^{2} n x^{2} + 600 \, b e^{2} x^{2} \log \left (c\right ) + 225 \, b d e n x + 600 \, a e^{2} x^{2} + 900 \, b d e x \log \left (c\right ) + 72 \, b d^{2} n + 900 \, a d e x + 360 \, b d^{2} \log \left (c\right ) + 360 \, a d^{2}}{1800 \, x^{5}} \]
[In]
[Out]
Time = 0.41 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.89 \[ \int \frac {(d+e x)^2 \left (a+b \log \left (c x^n\right )\right )}{x^6} \, dx=-\frac {x^2\,\left (10\,a\,e^2+\frac {10\,b\,e^2\,n}{3}\right )+6\,a\,d^2+x\,\left (15\,a\,d\,e+\frac {15\,b\,d\,e\,n}{4}\right )+\frac {6\,b\,d^2\,n}{5}}{30\,x^5}-\frac {\ln \left (c\,x^n\right )\,\left (\frac {b\,d^2}{5}+\frac {b\,d\,e\,x}{2}+\frac {b\,e^2\,x^2}{3}\right )}{x^5} \]
[In]
[Out]